Hi. I'm a junior and received an initial trading interview at jane st. capital. What's the firm's perception on the street? Also, can anyone give me some insight as to how the finance interview might go? All I know is what they told me, that it's going to evaluate my quantitative abilities. Thanks.
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Had an interview with them for FT a couple of weeks ago. Just be prepared to do mental math for 30 min. One question that I screwed up on was what's the closest integer to the square root of 1420.
Only thing I know about them is that they're very into brainteasers, as theflyingcow's post might suggest.
Here's a way to do the problem above quickly:
Notice that:
2^2 = 1^2 + 3 3^2 = 2^2 + 5 4^2 = 3^2 + 7
more generally, (n+1)^2 = n^2 + 2n + 1.
Now, let's try to get close to 1420. 30^2 = 900, and 40^2 = 1600. 1600 is pretty close, so let's start there.
From the relationship above, we know that 39^2 is around 1520, and 38^2 is around 1440. 38^2 is our answer.
Hey sherminator, just curious, are you majoring in a quantitative subject?
thanks.
I'm majoring in economics but am minoring in math (contemplating a math major as i've completed higher level coursework, indicated on my resume)... I got dinged 2nd round; 1st round was mental math and mental stats. 2nd round was pen & paper math/stats!
The question that got me dinged:
You and a roommate are hosting a party. You invite 10 other pairs of roommates. During the party you poll everyone at the party (excluding yourself) and ask how many hands each person shook. Two conditions:
1) Each person did not shake his roommate's hand. 2) Each person shook a different number of hands.
Question: How many hands did you roommate shake?
I answered this quesiton wrong and got dinged. I was doing fairly well up to that point as I was already over an hour in =)...
flying cow how did you make it to the later rounds? if so howd they go =p
i don't see how you can be more specific because htere isn't enough information to pin it down more?
Soo, what is the solution here? Any help :-)?
This one is a real bitch.
With problems like this, it's usually good to try to figure it out with a smaller number of variables and then see if you can generalize.
Let's say that there are N + 1 couples at the party (you invited N, and then there's you and your roommate). The most hands that anyone can shake is 2N (because you can't shake your own hand or your roommate's), so you know that for everyone except you to have shook a different number of hands, everyone has to have shook between 0 and 2N hands.
Let's say that one person shakes 2N hands. That means he shakes the hand of everyone at the party except himself and his roommate. So that person has shook 2N hands, his roommate has shook 0 hands, and everyone else has shook 1 hand. So, the roommate of the person who shook 2N hands can't shake any more hands, or else we won't be able to satisfy the condition that everyone shakes a different # of hands.
So let's move onto another person, who's already shook one hand. Say that person ends up shaking 2N - 1 hands, by shaking the hand of everyone at the party except himself, his roommate, and the person who's shook 0 hands. So at that point, one person has shook 2N hands, his roommate has shook 0 hands, one person has shook 2N - 1 hands, his roommate has shook 1 hand, and everyone else has shook 2 hands. Similarly, the roommate of the person who's shook 2N - 1 hands can't shake any more hands.
So, the pattern that's developing is that if a person shakes X hands, their roommate must shake 2N - X hands. This pattern will hold through the entire group. The problem is that there are 2N + 1 unique number of hands that a person at the party can shake, but 2N + 2 people at the party. So two people have to shake the same number of hands. Those two people have to be you and your roommate, because otherwise it couldn't be possible that everyone you polled shook a different number of hands. So what's the number that you and your roommate each shook? We've seen that if a person shook X hands, their roommate has to have shook 2N - X hands; X = 2N - X when X = N. So you and your roommate have both shaken N hands; in this case N = 10.
This problem is really hard; it took me a while to figure out, and I used pen and paper to draw diagrams. Doing it in your head is insanely hard. I've never heard of Jane Street, but if they're asking these kinds of questions in interviews they must be awesome.
Doesn't this violate the rule that each person must shake a different number of hands?
The requirement that no one shakes the same amount of hands applies to those polled, which is why you and your roommate have to shake the same number of hands.
Jane Street was started by some ex-Susquehanna guys. They are quant-oriented and love extremely smart guys who have some capacity for programming. They mostly do market-making and focus on single stock options. Having a trading background won't help you get the job.
great solution Hoover
getting an interview with jane street isnt hard. they will literally interview anyone.
but for every 1000 people they interview they only hire like 1 person. dont get ur hopes up
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