MailmanBitesDog:
512?

I did the same thing, saw the picture and ignored the 10x10x10 bit and worked it out for 3x3x3

EDIT: this was the answer for 3x3x3, it was changed just before replying.....lame post.

"After you work on Wall Street it’s a choice, would you rather work at McDonalds or on the sell-side? I would choose McDonalds over the sell-side.” - David Tepper
 

1000 total cubes Painted include 2- sides @ 100 cubes = 200 2- sides @ 80 cubes = 160 2- sides @ 64 cubes = 128 Total painted = 488 Total not painted = 512

Or the easier way to do it is just figure that it becomes an 8 x 8 x 8 cube.

If I got it wrong then my excuse is that I've spent too many years dragging my knuckles.

Thanks for the mid-day mental gymnastics.

They all have husbands and wives and children and houses and dogs, and, you know, they've all made themselves a part of something and they can talk about what they do. What am I gonna say? "I killed the president of Paraguay with a fork. How've you been?"
 
M. Blank:
1000 total cubes Painted include 2- sides @ 100 cubes = 200 2- sides @ 80 cubes = 160 2- sides @ 64 cubes = 128 Total painted = 488 Total not painted = 512

Or the easier way to do it is just figure that it becomes an 8 x 8 x 8 cube.

If I got it wrong then my excuse is that I've spent too many years dragging my knuckles.

Thanks for the mid-day mental gymnastics.

Yeah, I solved it the same way as an 8x8x8

 

Technically, a rubiks cube doesnt have any inner cubes so the answer would be zero.

[quote=rufiolove]When evaluating whether or not to post something on WSO, I think to myself, "would an idiot post this" and if the answer is yes, I do not post that thing...[/quote]
 
Best Response

For illustrative purposes, let's pretened the Rubik's cube is a dice (and we know the opposite sides of a dice add to 7).

Pretend the 'Dice' is sitting on a desk directly in front of you. The side facing you is a '1', and the opposite side is a '6'. The side facing the right is a '2', and the side facing the left is a '5'. The side touching the desk (facing down) is a '3', and the side facing up is '4'

Let n represent the number of cubes per edge on the dice, in this case, 10.

We know there are n^3 cubes in the dice (10^3 = 1000 in this example).

We are asked the number of cubes that will not be painted (ie. The "inside" cubes).

Let's count the number of cubes that are painted, and subtract that from the total number of cubes, making sure to avoid double counting.

Counting the cubes on side '1' and '6' will have no doubles, and is easy:

The number of cubes is n^2 x 2 = 200.

Now let's move to count sides '2' and '5': (n-2) x n x 2 = 8 x 10 x 2 = 160

Now we count sides '3' and '4': (n-2)^2 x 2 = 128

In total, 200 + 160 + 128 = 488 cubes are painted. This would leave 1000 - 488 = 512 cubes unpainted.

General formula: n^3 - (n^2 x 2) - [(n-2) x n x 2)] - (n-2)^2 x 2

 
protectedclass:
peepstache:
Technically, a rubiks cube doesnt have any inner cubes so the answer would be zero.

bingo. hired.

I'm going with this logic.

A 3x3x3 Rubik's Cube only has 26 individual cubes, so every single one would have at least one side covered in paint.

The question did not ask how many cubes would not have at least one side covered in paint on a 10x10x10 CUBE, it explicitly stated a Rubik's Cube; therefore, the answer is zero.

My name is Nicky, but you can call me Dre.
 
protectedclass:
Technically, a rubiks cube doesnt have any inner cubes so the answer would be zero.

bingo. hired.

Thanks.

If youre from HR at a bank please PM.

[quote=rufiolove]When evaluating whether or not to post something on WSO, I think to myself, "would an idiot post this" and if the answer is yes, I do not post that thing...[/quote]
 

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My name is Nicky, but you can call me Dre.

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