It takes 9 hours to fill a tank. It takes 11 hours to drain the tank. How long does it take to fill the tank while the drain plug is off, and the tank is draining as you fill?
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1 / (1/9 - 1/11)
common way to pose the same question is a monkey climbing up a pole climbs at 5 ft/hr and then falls 3 ft at the end of each hour - how long to climb a pole of x height.
mistake is to assume net 2ft/hour, but you need to bear in mind that once you reach the top, you don't fall
what job is this for? S&T?
In 1 hour, 1/9 of the tank's volume is filled (V/9) and in 1 hour, 1/11 of the tank's volume is drained (V/11), so effectively, in 1 hour V/9 - V /11 = 2V/99 of the tank is filled. So total time taken is volume/rate = V/(2V/99) = 99/2 hours, or 1/(1/9 - 1/11) as pussinboots said
I loathe this sort of SAT questions... I must have been good at this when I was at HS but now it's simply unbearable. The solution above is very clear but I wouldn't have come up with it on my own.
a coworker asked me and i wanted to confirm my 49.5 before giving it to him. thanks for the help guys - though i had no idea why he had this question, wouldn't tell me :/ -product control
im almost certain this is a problem off of the 11th edition from OG GMAT.
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