Do you think I can make it to the next round ?

Hi,

Yesterday I had third round telephone interview for Quant internship at BB (think GS/MS/JPM), everything happened well until I made a terrible calculation mistake at the end (I said BinomialCoefficient(6,3)=60 whereas it is equal to 20) leading me to a wrong result. The interviewer didnt tell me about my mistake during the interview. The thing is that I did very well during the rest of the interview, but there were not many questions, so I think I will be dinged with like 90 percent probability.

Regarding your experience, both as an interviewee or as an interviewer, what would you think of my chances ? zero ?

I am anxiously waiting for the response but I am not optimistic !

14 Comments
 

What's the point in your post ?

The thing is that if I got dinged because of a %^##!!& high school level calculation error, I would be really really disppointed, but I know that's the game. I have no other opportunities currently. I was on the wait list after superday at one of these banks but finally got dinged. I put on a crazy amount of efforts in the past three years to be able to got an interview at one of these banks, I went back to study after my mum passed away from cancer in 2012, and I had to pause my studies some years before because of personnal health problem.

Now, I would have no choice but to accept if I got dinged, no big deal User11221122

 

take it easy man. if you take what someone post on the internet that personally your not gonna last in an office job anyway.

And i have no clue lol.

 

I can safely tell you that you've made it through to the next round. Congratulations.

"After you work on Wall Street it’s a choice, would you rather work at McDonalds or on the sell-side? I would choose McDonalds over the sell-side.” - David Tepper
 

Hi MBBorBust,

Thanks for your answer.

The question was whats the most probable outcome after throwing 6 times in a row a coin with P(Head)=0.3. I compared P(NumberofHead=0) with P(NumberofHeads=1). Then I compared (PnumberofHeads=1) with P(NumlberofHeads=2). No mistake up to that point. I made the error when comparing P(numberofHeads=2) with P(numberOfheads=3) while calculating 6 choose 3. - choose 3 is 6 I think ! at least it must be an integer. So with my wrong calculations I got the result that having 3 Heads is the more probable, while the result is 2 heads....

So thats it, sorry for telling my life in the previous post but I am pretty disappointed to have made that mistake at this stage....

 

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