You are given 8 identical looking balls. One of them is heavier than the rest of the 7 (all the others weigh exactly the same). You are provided with a simple mechanical balance scale. How can you find the heavier ball by using the scale only twice?

The question is asked the wrong way or the answer on the website is wrong.....

The answer is correct just not communicated effectively

Ah I see. There deff should've been an extra sentence clarifying 2 groups of 3 with 2 balls off to the side.

You first take 6 balls leaving the other two out.

You break the 6 balls into 2 groups of 3 and weigh them. If the scale is balanced then you know the heavier ball is in the two you left out. Then you weight those two.

If the scale is not balanced you take the heavier side of the 2 groups. Then you weight one ball against another ball leaving one out. If the scale is balanced then you know the ball left out is the heavier one.

If the scale is unbalanced then you know the heavier side contains the heavier ball.

Last week my parents gave my wife and I a \$75 Chick-fil-A gift card for our 2nd anniversary. I am thankful.

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I like your name, I also like Chick-fil-a and wish there was one near me... Have a banana.

Interview question is bull. The answer provided requires the scale to be used 3 times,

Absolute truths don't exist... celebrated opinions do.

1) ooo___ooo
If equally weighted, then one of the two left out is the oddball.
If not equally weighted, take two from the heavier side.

2) o___o
If equally weighted, then the third one left out is the oddball.

Absolute truths don't exist... celebrated opinions do.