Actual Wall Street (trader) Interview questions
Here's two brainteasers for you:
- 1. (Don't read this one you are easily offended):
How can three men and one woman have mutually safe heterosexual intercourse with just two condoms ? Assume that no condom can break or leak, and that you cannot wash a used one.
2. A rock is dropped from the top of the Empire State Bldg. At what speed does it hit the ground, and how long does it take it to get there ?
The answers will follow -at the end of the day-.
does that ho have any cold sores?
and does she like to bite?
Like that.
Also this, fr. Cookies w/ Milken
Please, first one is from heard on the street, the second one is basic physics.
Maybe I'm reading the question incorrectly, but: 2 men use the condoms, 1 doesn't. Assuming the woman has nothing, the men are mutually safe.
Hits the ground in approximately 9-10 seconds travelling at ~100m/s.
op go diaf
(but yeah this question has been asked before and I won't spoil it)
Troll Answer: It hits the ground at a speed of zero. It's moving before impact and after impact, however the moment the rock impacts the ground the ground pushes back with equal force. It takes approximately no time to get there (there being the speed on impact) as the rock starts at a speed of zero.
Real Answer: Probably having to do with the terminal velocity of the rock and how long it takes to reach that. Wouldn't you need to know the weight of the rock? Me no don't do good science stuff.
old one...
//www.wallstreetoasis.com/forums/dirty-trading-puzzle
and StryfeDSP you really should have listened in sex-ed
Given the possibility the bitch has oral herpes, I can think of at least 4 other orifices that can get the job done.
All you need is a rubber hose, and a large kimono dragon.
.
Yes, that's the answer.
Was answered by ytnifny
If you want to detail, you can say: Ignoring air resistance,
We need to know how high Empire State is. From memory, about 100 floors/ each fl. about 4 meters high- so that's 400 meters high.
Using the simple equation of motion, v^2 = u^2 + 2gD, where v=final velocity, u=initial (zero), D = distance = 400 m, g (gravity)=9.8 m/s^2 ~ approx 10 m/s^2
v^2= 210400 = 8000 m^2/s^2, v= approx. 90 m/s
v= u + g*t, so t ~ 9 s.
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