sum of 1-100

Fuck me. I had a second round phone screen going very well until this question came up...

I had no fucking idea so I guessed 10,000. Turns out the answer is 5050 and there is an algebraic way to solve it.

Are people actually supposed to know this shit? or just memorize brain teasers....

16 Comments
 

Think about it this way, you have 50 pairs that add up to 101...

100+1 99+2 98+3 97+4 96+5 etc.

50*101 = 5050

In my book, brainteasers and absurd mental math problems do not prove anything. Unfortunately, some firms and people enjoy giving them and therefore you should attempt to gain exposure to as many as possible. This way, in the likelihood that your interviewer is a dick, you can pretend you have not heard it and talk your way through it.

 

You can be sure they're not going to be calling you back.

1+2+3+ ... + 98 + 99 + 100 = 50*(101) = 5050.

I think this is taught to 11-13 year olds these days.

Just Do It
 

I think u should at least recall 1 to n = [n * (n+1)]/2 and 1 to n^2 = [n * (n+1) * (2n +1)]/6 or how to split the pairs of numbers.

To be honest, for phone interviews I build back in my young days a simple Excel file with the most common questions. So sum 1 to n, 1 to n^2, 3rd roots, powers, permutations, combinations, etc. Didn't want to risk blacking out or something and I'm a lazy bitch. Seriously, if it's a phone interview: cheat! ;)

 
Best Response
DonMunichI think u should at least recall 1 to n = [n * (n+1)]/2 and 1 to n^2 = [n * (n+1) * (2n +1)]/6 or how to split the pairs of numbers.

To be honest, for phone interviews I build back in my young days a simple Excel file with the most common questions. So sum 1 to n, 1 to n^2, 3rd roots, powers, permutations, combinations, etc. Didn't want to risk blacking out or something and I'm a lazy bitch. Seriously, if it's a phone interview: cheat! ;)

Also, write a word document with all the potential questions you could be asked and your bullet point answers!

This is much simpler than you think.

The average of 1-100 is 101 / 2 or 55.5. Since the average is the sum of a set of figures divided by the number of figures in that set, you can get the sum by multiplying the average by the number of figures in the set. In this case there are 100 figures, the average is highest + lowest / 2 or (1+100)/2=55.5; so the sum is average x (number of figures) or 55.5 x 100 = 5,550.

 
charmander And brainteasers? Bro, wtf do you think a DCF is if you don't know some basic sums and series?
give me a break. everyone knows this is horseshit. the people who memorize these stupid little riddles will be fine.
 

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