For 55 graduating seniors who took the Miller Analogies Test (MAT), the following results were obtained: ∑ X = 2,942.5, ∑ X2 = 165,606.68 Use the normal distribution to answer the following questions.
15-What is the percentile rank of a score of 71?
Saw this in a technical book. Have not taken stats yet...so how would you suggest going about this? and what did you get as an answer?
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Variance = E[X^2]-(Ex^2) Variance = (165,606.68/55) - (2,942.5/55)^2 = 3011.031 - 2862.25 = 148.7805
std dev ~ 12.2 mean = 53.5
That's your distribution, and now you can get the percentile pretty straightforward. Lazy to calculate, but a quick reverse engineering from percentiles says it's around 92.5 percentile
hmm that is not what it has as the answer...
∑X2 is ∑(X^2), right? And by percentile you mean (100 * P(X = 71)), right?
If yes and yes, your book's smoking some strong stuff.
yes. that is correct
92.36%?
you forgot to divide by n=55 to get the average ...
could be a sampling vs pop calculation difference something to do with 1/root n or just root n bleh whats the answer
Its sad how quickly I forget this stuff. Two semesters to be exact.
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